x^2-12x+48=5

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Solution for x^2-12x+48=5 equation:


Simplifying
x2 + -12x + 48 = 5

Reorder the terms:
48 + -12x + x2 = 5

Solving
48 + -12x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
48 + -5 + -12x + x2 = 5 + -5

Combine like terms: 48 + -5 = 43
43 + -12x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
43 + -12x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-43' to each side of the equation.
43 + -12x + -43 + x2 = 0 + -43

Reorder the terms:
43 + -43 + -12x + x2 = 0 + -43

Combine like terms: 43 + -43 = 0
0 + -12x + x2 = 0 + -43
-12x + x2 = 0 + -43

Combine like terms: 0 + -43 = -43
-12x + x2 = -43

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -43 + 36

Reorder the terms:
36 + -12x + x2 = -43 + 36

Combine like terms: -43 + 36 = -7
36 + -12x + x2 = -7

Factor a perfect square on the left side:
(x + -6)(x + -6) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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